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Answered on 18 Apr Learn Work and energy

Nazia Khanum

Derivation of the Formula for Potential Energy Introduction to Potential Energy: Potential energy is the energy possessed by an object due to its position relative to other objects. It is a fundamental concept in physics and is crucial in understanding various phenomena, including gravitational and... read more

Derivation of the Formula for Potential Energy

Introduction to Potential Energy: Potential energy is the energy possessed by an object due to its position relative to other objects. It is a fundamental concept in physics and is crucial in understanding various phenomena, including gravitational and elastic potential energy.

Gravitational Potential Energy: Gravitational potential energy (PEg)(PEg) is the energy stored in an object due to its position in a gravitational field. The formula for gravitational potential energy is derived based on the gravitational force between two objects.

Formula for Gravitational Potential Energy: The formula for gravitational potential energy is given by:

PEg=mghPEg=mgh

Where:

  • mm is the mass of the object,
  • gg is the acceleration due to gravity (approximately 9.8 m/s29.8m/s2 on the surface of the Earth),
  • hh is the height or distance from a reference point.

Derivation of Gravitational Potential Energy Formula: The derivation starts with the definition of work done (WW) against gravity to raise an object to a height hh:

W=F⋅dW=F⋅d

Where:

  • FF is the force applied,
  • dd is the displacement.

In the case of lifting an object against gravity, the force required is the gravitational force (F=mgF=mg), and the displacement is the vertical height hh.

W=mg⋅hW=mg⋅h

Since work done is equal to the change in potential energy, we can equate it to the change in gravitational potential energy (ΔPEgΔPEg):

ΔPEg=WΔPEg=W

ΔPEg=mghΔPEg=mgh

This is the formula for gravitational potential energy, denoted by PEgPEg.

Conclusion: The formula for potential energy, particularly gravitational potential energy, is derived from the work done against gravity to raise an object to a certain height. It is given by PEg=mghPEg=mgh, where mm is the mass of the object, gg is the acceleration due to gravity, and hh is the height or distance from a reference point. Understanding this formula is essential in various fields of physics and engineering.

 
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Answered on 18 Apr Learn Work and energy

Nazia Khanum

Definition of Power Power is defined as the rate at which work is done or energy is transferred or converted. It measures how quickly energy is transferred or converted from one form to another. Unit of Power The unit of power is the watt (W), named after the Scottish engineer James Watt. Watt (W):... read more

Definition of Power

Power is defined as the rate at which work is done or energy is transferred or converted. It measures how quickly energy is transferred or converted from one form to another.

Unit of Power

The unit of power is the watt (W), named after the Scottish engineer James Watt.

  • Watt (W): The watt is defined as one joule per second. It is equivalent to the power required to do work at the rate of one joule per second.

Other units of power include:

  • Kilowatt (kW): Equal to 1000 watts. It is commonly used for larger electrical appliances and industrial machinery.
  • Megawatt (MW): Equal to one million watts. Used to measure the power output of large-scale power plants and industrial facilities.
  • Horsepower (hp): A unit of power originally defined as the power required to lift 550 pounds by one foot in one second. It is still commonly used to measure the power of engines, especially in the automotive industry. One horsepower is approximately equal to 746 watts.
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Answered on 18 Apr Learn Work and energy

Nazia Khanum

Understanding Potential Energy Potential energy is a fundamental concept in physics that refers to the energy possessed by an object due to its position or configuration relative to other objects. It's essentially the energy stored within a system that can be converted into other forms of energy.... read more

Understanding Potential Energy

Potential energy is a fundamental concept in physics that refers to the energy possessed by an object due to its position or configuration relative to other objects. It's essentially the energy stored within a system that can be converted into other forms of energy. Understanding potential energy is crucial in various fields, including physics, engineering, and chemistry.

Types of Potential Energy

Potential energy manifests in different forms depending on the nature of the system and the forces involved. Here are some common types of potential energy:

  1. Gravitational Potential Energy

    • Gravitational potential energy arises from the position of an object in a gravitational field. The gravitational potential energy UU of an object of mass mm at a height hh above a reference point (usually the Earth's surface) is given by the formula: U=mghU=mgh, where gg is the acceleration due to gravity (approximately 9.8 m/s29.8m/s2 on Earth).
  2. Elastic Potential Energy

    • Elastic potential energy is associated with the deformation of an elastic object, such as a spring or rubber band. When such objects are stretched or compressed, they store potential energy that can be released when they return to their original shape. The elastic potential energy UU stored in a spring is given by: U=12kx2U=21kx2, where kk is the spring constant (a measure of the stiffness of the spring) and xx is the displacement from the equilibrium position.
  3. Chemical Potential Energy

    • Chemical potential energy is stored within the chemical bonds of molecules. It is released or absorbed during chemical reactions. For example, when fuel burns, the chemical potential energy stored in its molecular bonds is converted into thermal energy and other forms of energy.
  4. Electrostatic Potential Energy

    • Electrostatic potential energy arises from the interaction between charged particles. Oppositely charged particles attract each other and possess potential energy due to their relative positions. The electrostatic potential energy UU between two point charges q1q1 and q2q2 separated by a distance rr is given by: U=k∣q1q2∣rU=rkq1q2, where kk is Coulomb's constant.
  5. Nuclear Potential Energy

    • Nuclear potential energy is stored within the nucleus of an atom. It is released or absorbed during nuclear reactions, such as nuclear fusion and fission. The tremendous amount of energy released in nuclear reactions is due to the conversion of nuclear potential energy into other forms of energy.

Understanding the various forms of potential energy is essential for analyzing physical systems, predicting behaviors, and engineering applications across different domains.

 
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Answered on 18 Apr Learn Work and energy

Nazia Khanum

Work and Energy Relationship Introduction Work and energy are fundamental concepts in physics that are closely related to each other. Understanding their relationship is crucial in comprehending various physical phenomena. Definition of Work Work, in the context of physics, is defined as the product... read more

Work and Energy Relationship

Introduction Work and energy are fundamental concepts in physics that are closely related to each other. Understanding their relationship is crucial in comprehending various physical phenomena.

Definition of Work Work, in the context of physics, is defined as the product of force applied on an object and the displacement of the object in the direction of the force. Mathematically, it is represented as:

Work=Force×Displacement×cos⁡(θ)Work=Force×Displacement×cos(θ)

where:

  • ForceForce is the magnitude of the force applied,
  • DisplacementDisplacement is the magnitude of the displacement of the object,
  • θθ is the angle between the force vector and the displacement vector.

Definition of Energy Energy is the capacity to do work. It exists in various forms such as kinetic energy, potential energy, thermal energy, etc. The total energy of a system remains constant in an isolated system according to the law of conservation of energy.

Relationship Between Work and Energy The relationship between work and energy can be understood through the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy. Mathematically, it can be expressed as:

Work=ΔKinetic EnergyWork=ΔKinetic Energy

This theorem implies that when work is done on an object, it either gains or loses kinetic energy depending on the direction of the force applied.

Forms of Energy Energy exists in various forms, including:

  • Kinetic Energy: Energy possessed by a moving object.
  • Potential Energy: Energy stored in an object due to its position or configuration.
  • Mechanical Energy: The sum of kinetic and potential energy in a system.
  • Thermal Energy: Energy associated with the temperature of an object.

Conservation of Energy According to the law of conservation of energy, energy can neither be created nor destroyed, it can only be converted from one form to another. This principle is crucial in understanding various physical phenomena and is a fundamental concept in physics.

Applications The relationship between work and energy finds applications in various fields, including:

  • Mechanics: Understanding the motion of objects and the forces acting upon them.
  • Engineering: Designing machines and structures by considering energy conservation principles.
  • Thermodynamics: Analyzing heat transfer and energy conversion processes.

Conclusion Work and energy are interconnected concepts in physics. The work-energy theorem provides a fundamental relationship between the work done on an object and the change in its kinetic energy. Understanding this relationship is essential for analyzing and predicting the behavior of physical systems.

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Answered on 18 Apr Learn Work and energy

Nazia Khanum

Example of Negative Work Done on an Object Introduction: In physics, work done on an object is defined as the energy transferred to or from the object by means of a force acting on it. When the force and the displacement are in the same direction, work done is considered positive, whereas when they... read more

Example of Negative Work Done on an Object

Introduction: In physics, work done on an object is defined as the energy transferred to or from the object by means of a force acting on it. When the force and the displacement are in the same direction, work done is considered positive, whereas when they are in opposite directions, work done is negative.

Example: Lifting an Object Upwards:

  • Scenario: Imagine lifting a box off the ground to place it on a shelf.
  • Force and Displacement: In this scenario, the force exerted by the person is upwards, while the displacement of the box is also upwards.
  • Direction of Work: Since the force and displacement are in the same direction (upwards), the work done on the box is positive.
  • Magnitude of Work: The magnitude of the work done is determined by the force exerted and the distance over which it is applied.

Example: Lowering an Object Downwards:

  • Scenario: Now, consider lowering the same box back to the ground from the shelf.
  • Force and Displacement: Here, the force exerted by the person is still upwards, but the displacement of the box is downwards.
  • Direction of Work: The force and displacement are in opposite directions, with the force opposing the displacement.
  • Negative Work: As a result, the work done on the box is negative because the force exerted by the person is against the direction of motion.
  • Magnitude of Work: The magnitude of the work done is still determined by the force exerted and the distance over which it is applied, but with a negative sign to indicate the direction.

Conclusion: In conclusion, when an object is moved in a direction opposite to the force applied, the work done on the object is negative. This concept is crucial in understanding the transfer of energy and the behavior of objects under the influence of forces.

 
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Answered on 18 Apr Learn Motion

Nazia Khanum

i) Motion of a Car around a Curve: The kind of motion exhibited by a car moving with constant speed turning around a curve is uniform circular motion. In this motion, the car maintains a constant speed while continuously changing its direction due to the curve, resulting in a circular path. ii) Motion... read more

i) Motion of a Car around a Curve:

  • The kind of motion exhibited by a car moving with constant speed turning around a curve is uniform circular motion.
  • In this motion, the car maintains a constant speed while continuously changing its direction due to the curve, resulting in a circular path.

ii) Motion of an Electron Orbiting around a Nucleus:

  • The kind of motion displayed by an electron orbiting around a nucleus is uniform circular motion.
  • In an atom, electrons revolve around the nucleus in circular paths at a constant speed, maintaining a stable orbit.

Answer to Question (b):

Given:

  • Radius of circular orbit, r=36,000r=36,000 km
  • Time taken to revolve around the Earth, T=24T=24 hours

To Calculate:

  • Speed of the artificial satellite in its orbit.

Solution:

  1. Convert the time from hours to seconds since speed is measured in meters per second.

    • 2424 hours ×60×60 minutes/hour ×60×60 seconds/minute = 86,40086,400 seconds.
  2. Apply the formula for the speed of an object in circular motion:

    • Speed v=2πrTv=T2πr
  3. Substitute the given values into the formula:

    • Speed v = \frac{2 \pi \times 36,000 km}{86,400 ) seconds }
    • Speed v=72,000π86,400v=86,40072,000π km/s
    • Speed v=20π24v=2420π km/s
    • Speed v=5π6v=65π km/s
    • Speed v≈2.62v≈2.62 km/s (approximately)

Result:

  • The speed of the artificial satellite in its circular orbit around the Earth is approximately 2.622.62 km/s.
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Answered on 18 Apr Learn Motion

Nazia Khanum

Understanding Uniform and Non-Uniform Motion Uniform Motion: Uniform motion refers to the movement of an object at a constant speed in a straight line, maintaining the same velocity throughout its journey. In this type of motion, the object covers equal distances in equal intervals of time. Example... read more

Understanding Uniform and Non-Uniform Motion

Uniform Motion: Uniform motion refers to the movement of an object at a constant speed in a straight line, maintaining the same velocity throughout its journey. In this type of motion, the object covers equal distances in equal intervals of time.

Example of Uniform Motion:

  • A Car Traveling on a Highway:
    • Suppose a car is cruising on a straight highway at a constant speed of 60 miles per hour (mph).
    • Regardless of the time of day or road conditions, if the car maintains this speed without any acceleration or deceleration, it's considered to be in uniform motion.

Non-Uniform Motion: Non-uniform motion occurs when an object changes its speed or direction over time. Unlike uniform motion, the velocity of an object in non-uniform motion is not constant; it may vary at different points during its journey.

Example of Non-Uniform Motion:

  • A Roller Coaster Ride:
    • Consider a roller coaster moving along its track.
    • As it ascends a hill, its speed decreases due to gravity pulling it back.
    • Then, as it descends, its speed increases rapidly, reaching maximum velocity at the bottom of the hill.
    • Throughout the ride, the roller coaster's speed varies, making it an example of non-uniform motion.
 
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Answered on 18 Apr Learn Motion

Nazia Khanum

Distance-Time Graph for Uniform and Non-Uniform Motion Uniform Motion: In uniform motion, the object covers equal distances in equal intervals of time. The distance-time graph for uniform motion is a straight line inclined to the time axis. Non-Uniform Motion: In non-uniform motion, the object covers... read more

Distance-Time Graph for Uniform and Non-Uniform Motion

Uniform Motion:

  • In uniform motion, the object covers equal distances in equal intervals of time.
  • The distance-time graph for uniform motion is a straight line inclined to the time axis.

Non-Uniform Motion:

  • In non-uniform motion, the object covers unequal distances in equal intervals of time.
  • The distance-time graph for non-uniform motion is curved.

Solution:

Given Data:

  • Initial velocity (u) = 0 m/s (as the bus starts from rest)
  • Acceleration (a) = 0.1 m/s²
  • Time (t) = 2 minutes = 120 seconds

(a) Speed Acquired:

  • Using the equation of motion: v=u+atv=u+at
  • v=0+(0.1×120)v=0+(0.1×120)
  • v=12 m/sv=12m/s

(b) Distance Travelled:

  • Using the equation of motion: s=ut+12at2s=ut+21at2
  • s=(0×120)+12(0.1×1202)s=(0×120)+21(0.1×1202)
  • s=0+12(0.1×14400)s=0+21(0.1×14400)
  • s=12(1440)s=21(1440)
  • s=720 ms=720m

Summary:

  • The speed acquired by the bus is 12 m/s12m/s.
  • The distance travelled by the bus is 720 m720m.
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Answered on 18 Apr Learn Motion

Nazia Khanum

Uniform Acceleration Definition: Uniform acceleration refers to a situation where an object's velocity changes at a constant rate over time. In other words, the object's speed increases or decreases by the same amount in each successive equal interval of time. Acceleration of a Body with Uniform Velocity:... read more

Uniform Acceleration

Definition: Uniform acceleration refers to a situation where an object's velocity changes at a constant rate over time. In other words, the object's speed increases or decreases by the same amount in each successive equal interval of time.

Acceleration of a Body with Uniform Velocity: When a body is moving with uniform velocity, its acceleration is zero. This means that the object maintains a constant speed and direction, hence no change in velocity, and consequently, no acceleration.

Magnitude of Displacement for a Particle Moving Over Three Quarters of a Circle

Given:

  • Particle moves over three quarters of a circle of radius rr.

Calculation:

  1. Circumference of the Circle:

    • Circumference CC of a circle with radius rr is given by C=2πrC=2πr.
  2. Three Quarters of the Circle:

    • Three quarters of the circumference is 34×2πr43×2πr.
  3. Magnitude of Displacement:

    • The displacement is the shortest distance between the initial and final positions.
    • When a particle moves over three quarters of a circle, its displacement is equal to the diameter of the circle.
    • Diameter DD of the circle with radius rr is given by D=2rD=2r.

Result:

  • The magnitude of the displacement for a particle moving over three quarters of a circle of radius rr is equal to 2r2r.
 
 
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Answered on 18 Apr Learn Motion

Nazia Khanum

Solution: Given Data: Initial velocity, u=54 km/hu=54km/h Final velocity, v=72 km/hv=72km/h Time, t=10 secondst=10seconds Conversion: To perform calculations, we need to convert velocities from km/h to m/s. Conversion: 1 km/h = 13.63.61 m/s Converting Initial Velocity: u=54 km/h×13.6=15 m/su=54km/h×3.61=15m/s Converting... read more

Solution:

Given Data:

  • Initial velocity, u=54 km/hu=54km/h
  • Final velocity, v=72 km/hv=72km/h
  • Time, t=10 secondst=10seconds

Conversion: To perform calculations, we need to convert velocities from km/h to m/s.

Conversion: 1 km/h = 13.63.61 m/s

Converting Initial Velocity: u=54 km/h×13.6=15 m/su=54km/h×3.61=15m/s

Converting Final Velocity: v=72 km/h×13.6=20 m/sv=72km/h×3.61=20m/s

(i) Acceleration (aa):

Formula: a=v−uta=tv−u

Substituting Values: a=20 m/s−15 m/s10 sa=10s20m/s−15m/s

Calculation: a=5 m/s10 s=0.5 m/s2a=10s5m/s=0.5m/s2

(ii) Distance Covered (ss):

Formula: s=ut+12at2s=ut+21at2

Substituting Values: s=(15 m/s×10 s)+12×0.5 m/s2×(10 s)2s=(15m/s×10s)+21×0.5m/s2×(10s)2

Calculation: s=(150 m)+0.5×5×100=150+250=400 ms=(150m)+0.5×5×100=150+250=400m

Answer: (i) Acceleration a=0.5 m/s2a=0.5m/s2 (ii) Distance Covered s=400 ms=400m

Therefore, the bus accelerates at 0.5 m/s20.5m/s2 and covers a distance of 400 m400m during this interval.

 
 
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