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Nitrogen dioxide (NO2NO2) dimerizes to form dinitrogen tetroxide (N2O4N2O4) due to the presence of unpaired electrons on each nitrogen atom in the NO2NO2 molecule. This dimerization process is a result of the tendency of molecules with unpaired electrons to pair up and form more stable configurations.

In the gas phase, NO2NO2 exists predominantly as a reddish-brown dimer, N2O4N2O4, which is colorless. The dimerization reaction can be represented as:

2NO2⇌N2O42NO2⇌N2O4

This process is reversible, meaning that N2O4N2O4 can dissociate back into NO2NO2 molecules. The equilibrium between NO2NO2 and N2O4N2O4 depends on factors such as temperature, pressure, and concentration.

The dimerization of NO2NO2 to form N2O4N2O4 is an important reaction in atmospheric chemistry. In polluted urban environments, NO2NO2 is often emitted from vehicles and industrial sources. When NO2NO2 reacts with other pollutants and undergoes dimerization to form N2O4N2O4, it can contribute to the formation of smog and other harmful atmospheric conditions.

In H3PO2, also known as hypophosphorous acid, the oxidation number of hydrogen (H) is typically +1.

The sum of the oxidation numbers in a neutral molecule must equal zero. Since there are three hydrogen atoms, each with an oxidation number of +1, their total contribution is +3.

For oxygen (O), the typical oxidation number is -2, except in peroxides and when it's bonded to fluorine. In H3PO2, oxygen's oxidation number is -1.

Given that the overall charge of the molecule is zero, and knowing the oxidation numbers of hydrogen and oxygen, you can calculate the oxidation number of phosphorus (P).

Let's denote the oxidation number of phosphorus as xx:

(+1×3)+(−1×2)+x=0(+1×3)+(−1×2)+x=0

3−2+x=03−2+x=0

1+x=01+x=0

x=−1x=−1

So, in H3PO2, the oxidation number of phosphorus is -1.

(i) Transition elements generally form colored compounds:

The color exhibited by transition metal compounds arises from the d-d transition, which involves the movement of electrons between the d orbitals of the metal ions. Transition metals have partially filled d orbitals, which allow for the absorption of visible light. When light strikes a transition metal complex, it can promote an electron from a lower-energy d orbital to a higher-energy d orbital, resulting in the absorption of certain wavelengths of light and the reflection or transmission of others. The color observed depends on the energy difference between the d orbitals involved in the transition.

The intensity and nature of the color can be influenced by various factors such as the oxidation state of the metal ion, the ligands surrounding the metal ion, and the coordination geometry of the complex. Ligands with different electron-donating abilities can lead to different splitting patterns of the d orbitals, resulting in different absorption spectra and hence different colors.

(ii) Zinc is not regarded as a transition element:

Zinc is often not considered a transition element because it lacks partially filled d orbitals in its common oxidation states. In its most common oxidation state, +2, the 3d orbitals are completely filled, which means there are no available d electrons for d-d transitions to occur. Therefore, zinc typically forms colorless compounds.

Transition metals, by definition, have incompletely filled d orbitals in at least one oxidation state, which allows them to exhibit characteristic transition metal properties such as forming colored compounds and acting as catalysts. Since zinc does not fulfill this criterion, it is often excluded from the list of transition elements despite being located in the d-block of the periodic table.

(i) Copper (I) ion is not known in aqueous solution primarily because copper tends to exist in the +2 oxidation state in aqueous solutions. This is due to the relative stability of the Cu(II) oxidation state compared to Cu(I) in aqueous environments. The standard reduction potential for the Cu(II)/Cu(I) couple is higher than that for many other metal ions, making the Cu(II) state more stable in water. Additionally, Cu(II) ions readily hydrolyze in water, forming insoluble Cu(OH)₂, further reducing the concentration of Cu(I) ions in solution.

(ii) Actinoids exhibit a greater range of oxidation states than lanthanoids due to the presence of f-orbitals in their electron configurations. Actinoid elements have more extended series of f-orbitals available for electron configuration, leading to a greater variety of possible oxidation states. The lanthanoid series, on the other hand, have electrons filling 4f orbitals, which are relatively shielded from the outer environment by the 5s and 5p orbitals. As a result, lanthanoid elements generally exhibit fewer accessible oxidation states compared to actinoids. Additionally, the actinoid series is longer than the lanthanoid series, providing more elements with a greater variety of electron configurations and oxidation states.

Sure, let's break down each of these statements:

(i) Transition metals generally form colored compounds: Reason: The color of transition metal compounds arises due to the presence of partially filled d orbitals in the transition metal ions. When light interacts with these compounds, electrons in the d orbitals can absorb certain wavelengths of light, causing them to transition to higher energy levels. The absorbed wavelengths correspond to the complementary color of the one observed, resulting in the compound appearing colored. This phenomenon is known as d-d transition. The energy gap between the d orbitals varies depending on the metal ion and its oxidation state, leading to a wide range of colors observed in transition metal compounds.

(ii) Manganese exhibits the highest oxidation state of +7 among the 3d series of transition elements: Reason: Manganese, being a member of the 3d transition metal series, can exhibit multiple oxidation states due to the availability of its d orbitals for electron transfer. However, among the 3d series elements, manganese has the highest number of unpaired electrons available in its 3d orbitals, which allows it to achieve its highest oxidation state of +7. This occurs in compounds like potassium permanganate (KMnO4), where manganese is in the +7 oxidation state. The ability of manganese to access this high oxidation state is attributed to its electron configuration and its position within the periodic table.

These are interesting observations that can be explained by considering the electronic configurations and trends in oxidation states across transition metals.

(i) Cr2+ is reducing in nature while Mn3+ is an oxidizing agent: This can be explained by looking at the electronic configurations of Cr2+ and Mn3+.

• Cr2+ has an electronic configuration of [Ar] 3d4, where it has a half-filled d orbital. Half-filled orbitals have lower energy due to greater exchange energy, making it energetically favorable for Cr2+ to lose electrons and become Cr3+ in order to achieve a stable half-filled d orbital, thus acting as a reducing agent.

• On the other hand, Mn3+ has an electronic configuration of [Ar] 3d4, which is one electron short of achieving a stable half-filled d orbital. So, Mn3+ tends to gain an electron to achieve a stable half-filled d orbital, making it an oxidizing agent as it oxidizes other species by accepting electrons.

(ii) In a transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series: This observation can be explained by considering the trends in the filling of d orbitals across the transition series.

• At the beginning of the transition series, elements have fewer d electrons available for oxidation, limiting the number of oxidation states they can exhibit.

• Toward the middle of the series, there's a peak in the number of oxidation states exhibited. This is because these elements have a balance between gaining and losing electrons, allowing them to exhibit a wider range of oxidation states.

• Towards the end of the series, the number of oxidation states generally decreases as elements have a higher tendency to gain electrons rather than lose them, leading to fewer oxidation states.

So, the middle of the transition series tends to have elements that can exhibit the greatest number of oxidation states due to the balance between gaining and losing electrons facilitated by their electronic configurations.

Linkage isomerism occurs in coordination compounds where the ligand can coordinate through different atoms. One common example is the linkage isomerism in nitro and nitrito complexes.

Consider the complex [Co(NH₃)₅(NO₂)]²⁺. Here, the nitro ligand (NO₂) can bind to the central cobalt atom either through the nitrogen atom (forming a nitro ligand) or through one of the oxygen atoms (forming a nitrito ligand).

So, the two possible linkage isomers of this complex are:

1. [Co(NH₃)₅(NO₂)]²⁺ (Nitro linkage isomer)
2. [Co(NH₃)₅(ONO)]²⁺ (Nitrito linkage isomer)

In the nitro linkage isomer, the nitrogen atom of the NO₂ ligand is coordinated to the cobalt atom, while in the nitrito linkage isomer, one of the oxygen atoms of the NO₂ ligand is coordinated to the cobalt atom.