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CBSE Class 9 Mathematics Worksheet
Unit 4-Geometry - Construction
State True/False: A can be constructed in which AC = 10 cm, and BC = 7 cm, AB =6 cm.
Construct a triangle ABC in which BC = 6 cm, and .
State True/False: To construct a triangle given its base, a base angle and the sum of the other two sides is required.
Construct a rhombus whose side is of length 4 cm and one of its angles is .
Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm.
A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm.
Construct a square of side 4 cm.
State True/False: An angle of can be constructed with the help of a ruler or compass.
Construct a rectangle whose adjacent sides are of lengths 6 cm and 4.5 cm and one of its adjacent angle is .
Construct a right triangle whose base is 12cm and sum of its hypotenuse and other side is 18 cm.
Construct a triangle ABC in which, ∠B = , ∠C = and its perimeter is 12 cm.
Draw an angle of 85° with the help of a protractor and bisect it.
State True/False: To construct a triangle given its base, a base angle and the sum of the other two sides is required.
State True/False: An angle of can be constructed with the help of a ruler or compass.
Choose the correct option:
The construction of a , given that PQ = 7 cm, is not possible when sum of PR and QR is equal to _______.
Construct an equilateral triangle if its side is 6 cm.
Construct a triangle XYZ in which YZ = 6 cm, ∠Y = 60° and XZ + XY = 8 cm.
Choose the correct option:
The construction of a , given that BC = 5 cm, is possible when difference of AB and AC is equal to ________.
Construct an angle bisector of an angle of
Choose the correct option:
With the help of a ruler and a compass, it is possible to construct an angle of ________.
CBSE Class 9 Mathematics Worksheet
Unit 4-Geometry - Construction
Answers
To be constructed
Solution:
Steps of construction:
1). Draw a line segment BC = 6 cm.
2). Draw and .
3). Get the intersection point A on BY and CP.
ABC is the rquired triangle.
To be constructed.
Solution:
Steps to construction:
1). Draw a line segment AB = 4 cm.
2). At A, draw an angle PAB =
3). With A as centre draw an arc of radius 4 cm, to intersect X AX at D.
4). With D and B as centre, draw arcs of radius 4 cm to intersect each other at C.
5). Join CD and BC
ABCD is the required rhombus.
To be constructed
Solution:
Steps of construction:
1). Draw a line segment AB of length = 5 cm.
2). At B draw angle B = 90.
3). With B as center and radius = 3.5 cm, draw an arc, cutting BE at C.
4). With A as center and radius = 3.5 cm, draw an arc.
5). With C as centre and radius = 5 cm, draw another arc cutting the previous arc at D.
6). Join AD and CD.
ABCD is the required rectangle.
To be constructed
Solution:
Steps to construction:
1). Draw a ray BX and cut off a line segment BC = 3.5 cm.
2). Construct angle B =
3). From BY cut off line segment BD = 5.5 cm.
4). Join CD.
5). Draw the perpendicular bisector of CD, intersecting BD at point A.
6). Join AC
ABC is a required triangle.
To be constructed
Solution:
Steps to construction:
1). Draw a line segment AB = 4 cm.
2). With B as centre, draw an angle of .
3). With B as centre and radius = 4 cm, cut an arc on C.
4). With A as centre and radius = 4 cm, draw an arc.
5). With C as centre and radius = 4 cm, draw an arc intersecting the previous arc at D.
6). Join AD and CD.
ABCD is the required square.
To be constructed
To be constructed
Solution:
Steps of construction:
1). Draw a line segment BC = 12 cm.
2). Draw an
3). Cut off a line segment BD = 18 cm.
4). Join CD
5). Draw the perpendicular bisector of CD, intersecting BD at a point A.
6). Join AC.
ABC is the required triangle.
To be constructed
Solution:
Steps of construction:
1). Draw a line segment XY = 12 cm.
2). With X as centre, draw angle X = and with Y as centre draw angle Y = .
3). Draw angle bisectors on X and Y intersecting at A.
4). Draw line bisector of XA and AY respectively. Name the intersecting points on XY as B and C.
5). Join AB and AC.
ABC is the required triangle
To be constructed
Solution:
Steps of construction:
1). Draw a line PQ.
2). Take any point L on this line.
3). Construct perpendicular AL on PQ.
4). Cut a line segment AD from D equal to 6 cm.
5). Make angles equal to 30 degree at A on both sides of AD.
Then, ABC is a required triangle.
To be constructed
Solution:
Steps to construction:
1). Draw a line segment YZ = 6 cm.
2). Draw angle Y =
3). With Center Y and radius 8 cm, make an arc which intersects YA at B.
4). Join B to X.
5). Draw a perpendicular bisector of segment BX intersecting the line segment BY at point Z.
6). Join Z to X.
XYZ is the required triangle.
To be constructed