Your Worksheet is Ready
CBSE Class 10 Mathematics Worksheet
UNIT V: Trigonometry - Some Applications of Trigonometry
2
B)0
C)3
D)4
1
B)9
C)8
D)0
If sinA=4/5 then cotA+cosecA=?
2
B)3
C)5
D)4
2(sin6A+cos6A)-3(sin4A+cos4A) is equal to
1
B)0
C)-1
D)2
sin2A=2sinA is true when A=
0degree
B)30degree
C)45degree
D)60degree
As observed from the top of a light house 100m above sea level, the angle of depression of a ship, sailing directly towards it, change from 30degree to 45degree. Determine the distance travelled by the ship during the period of observation
73.2
B)37.2
C)27.3
D)77.2
0
B)1
C)sin2B = 2sinB is true when B is equal to
90°
B)60°
C)30°
D)0°
If y sin 45° cos 45° = tan2 45° – cos2 30°, then y =
-1/2
B)1/2
C)-2
D)2
tan2A=?
2tanA/1+tan^2A
B)2tanA/1-tan^2A
C)2tanA/1+tan2A
D)2tanA/1-tan2A
TAN 450
1/(Square root of 2)
B)0
C)1/2
D)1/4
If sec A + tan A = x, then sec A =
(x2-1)/x
B)(x2-1)/2x
C)(x2+1)/x
D)(x2+1)/2x
If x tan 45° sin 30° = cos 30° tan 30° , then x is equal to
1/2
B)1/√2
C)√3
D)1
What is the minimum value of sin A, 0 ≤ A ≤ 90°
1
B)0
C)-1
D)1/2
Two pillars of equal height and either side , which is 100m wide . The angles of elevation of the top of the pillars are 60 degree and 30degree at a point on the road between the pillars. find the position of the point between the pillars
25mts, 75mts
B)50mts, 75mts
C)75mts, 75mts
D)50mts, 50mts
If secθ = x + 1/4x , find sinθ+cosθ ?
6/5
B)5/7
C)7/5
D)4/5
Given that sin θ = a/b, then tan θ =
b/√(b2-a2)
B)√(b2-a2)/b
C)a/√(b2-a2)
D)√(b2-a2)/a
A tower subtends an angle of 30degree at a point on the same level as its foot. At a second point h mts above the first, the depression of the foot of the tower is 60degree. The height of the tower is
h/2
B)h/3
C)3h
D)√h
In a triangle B=90º, C =θ. What is the value of tanθ.sinθ?
cos²θ/sin²θ
B)sin²θ/cos²θ
C)secθ-cosθ
D)cosθ-secθ
If sin A – cos A = 0, then the value of sin4 A + cos4 A is
1
B)2
C)3/4
D)1/2
CBSE Class 10 Mathematics Worksheet
UNIT V: Trigonometry - Some Applications of Trigonometry
Answers
Solution:
solve at x = 1, secθ = 5/4
so, sinθ + cosθ= (3/5) + (4/5) = 7/5
