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Learn Exercise 6.2 with Free Lessons & Tips

Find the square of the following numbers

(i) 32 (ii) 35

(iii) 86 (iv) 93

(v) 71 (vi) 46#new_question_

Write a Pythagorean triplet whose one member is

(i) 6 (ii) 14

(iii) 16 (iv) 18

(i) 322 = (30 + 2)2

= 30 (30 + 2) + 2 (30 + 2)

= 302 + 30 × 2 + 2 × 30 + 22

= 900 + 60 + 60 + 4

= 1024

(ii) The number 35 has 5 in its unit’s place. Therefore,

352 = (3) (3 + 1) hundreds + 25

= (3 × 4) hundreds + 25

= 1200 + 25 = 1225

(iii) 86= (80 + 6)2

= 80 (80 + 6) + 6 (80 + 6)

= 802 + 80 × 6 + 6 × 80 + 62

= 6400 + 480 + 480 + 36

= 7396

(iv) 93= (90 + 3)2

= 90 (90 + 3) + 3 (90 + 3)

= 902 + 90 × 3 + 3 × 90 + 32

= 8100 + 270 + 270 + 9

= 8649

(v) 71= (70 + 1)2

= 70 (70 + 1) + 1 (70 + 1)

= 702 + 70 × 1 + 1 × 70 + 12

= 4900 + 70 + 70 + 1

= 5041

(vi) 46= (40 + 6)2

= 40 (40 + 6) + 6 (40 + 6)

= 402 + 40 × 6 + 6 × 40 + 62

= 1600 + 240 + 240 + 36

= 2116

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