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Answered on 29 Apr Learn Chemistry +1 Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

It is soluble in water and it is prepared by reacting silica sand and sodium carbonate at a high temperature ranging from 1200 to 1400OC. Aqueous solution of sodium silicate is called water glass.
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Answered on 29 Apr Learn Chemistry +1 Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

(a) On moving down the alkali group, the ionic and atomic sizes of the metals increase. The given alkali metal ions can be arranged in the increasing order of their ionic sizes as: Li+ < Na+ < K+ < Rb+ < Cs+ Smaller the size of an ion, the more highly is it hydrated. Since Li+ is the smallest,... read more

(a) On moving down the alkali group, the ionic and atomic sizes of the metals increase. The given alkali metal ions can be arranged in the increasing order of their ionic sizes as:

Li+ < Na+ < K< Rb+ < Cs+

Smaller the size of an ion, the more highly is it hydrated. Since Li+ is the smallest, it gets heavily hydrated in an aqueous solution. On the other hand, Csis the largest and so it is the least hydrated. The given alkali metal ions can be arranged in the decreasing order of their hydrations as:

Li+ > Na+ > K> Rb+ > Cs+

Greater the mass of a hydrated ion, the lower is its ionic mobility. Therefore, hydrated Li+ is the least mobile and hydrated Cs+ is the most mobile. Thus, the given alkali metal ions can be arranged in the increasing order of their mobilities as:

Li+ < Na+ < K< Rb+ < Cs+

(b) Unlike the other elements of group 1, Li reacts directly with nitrogen to form lithium nitride. This is because Li+ is very small in size and so its size is the most compatible with the N3– ion. Hence, the lattice energy released is very high. This energy also overcomes the high amount of energy required for the formation of the N3– ion.

(c) Electrode potential (E°) of any M2+/M electrode depends upon three factors:

(i) Ionisation enthalpy

(ii) Enthalpy of hydration

(iii) Enthalpy of vaporisation

The combined effect of these factors is approximately the same for Ca, Sr, and Ba. Hence, their electrode potentials are nearly constant.

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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

The gas used in the manufacture of Vanaspati Ghee from Vanaspati Oil is Hydrogen. At high pressure, in the presence of nickel catalyst, hydrogen is mixed with vegetable oils which turn them into vegetable ghee. This process is called the hydrogenation of oils.
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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

Thus, the process of adsorption of hydrogen on a metal surface is known as Occlusion and the hydrogen is said to be occluded hydrogen.
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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

H2O2 can be reduced to H2O as well as it can be oxidised to O2. Hence, it can act as an oxidizing agent by itself getting reduced to H2O as well as it can act as a reducing agenct by getting oxidized to O2. Therefore, it can act as oxidizing as well as reducing agent.
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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

H 2O 2 is unstable under alkaline conditions. Decomposition is catalysed by various redox-active ions or compounds, including most transition metals and their compounds (e.g. manganese dioxide ( MnO 2), silver, and platinum). read more

22 is unstable under alkaline conditions. Decomposition is catalysed by various redox-active ions or compounds, including most transition metals and their compounds (e.g. manganese dioxide ( MnO 2), silver, and platinum).

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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

Temporary Hardness: Caused by bicarbonates of calcium and magnesium. This hardness can be easily removed by boiling, as the bicarbonates decompose to insoluble carbonates that can be filtered out. Permanent Hardness: A tougher nut to crack, arising from chlorides and sulfates of calcium and magnesium... read more

Temporary Hardness: Caused by bicarbonates of calcium and magnesium. This hardness can be easily removed by boiling, as the bicarbonates decompose to insoluble carbonates that can be filtered out.

Permanent Hardness: A tougher nut to crack, arising from chlorides and sulfates of calcium and magnesium.

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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

Refining process of fossil fuels. Act as a reducing agent for the treatment of metallic ores. It is used in the manufacturing process of different products such as urea, hydrochloric acid, nitric acid, methanol, metal hydrides, hydrogen chloride, and fertilizers.
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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

Hydrogen is not preferred in balloons because it is combustible and explosive. It can catch fire readily. To prevent accidents, dihydrogen is not preferred instead helium is preferred in balloons.
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Answered on 30 Apr Learn Chemistry +1 Hydrogen

Deepika Agrawal

"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."

A Conc. H2SO4 cannot be used because it acts as oxidizing agent also and gets reduced to SO2. Zn + dil H2SO → ZnSO4 + 2H2O + SO2 b Pure Zn is not used because it is non-porous and reaction will be slow. The impurities in Zn help in constitute of electrochemical couple and speed up reaction. read more

A Conc. H2SO4 cannot be used because it acts as oxidizing agent also and gets reduced to SO2. Zn + dil H2SO → ZnSO4 + 2H2O + SO2 b Pure Zn is not used because it is non-porous and reaction will be slow. The impurities in Zn help in constitute of electrochemical couple and speed up reaction.

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