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A man buys a cycle for Rs 1400 and sells it at a loss of 15%. What is the selling price of the cycle?

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Loss = Loss%/100 * CP = (15/100) * 1400 = 210 SP = CP - Loss = 1400 - 210 = 1190
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Cost price of the cycle is 1400 Loss %=15%=loss/cp*100=loss/1400*100= Loss=210 Loss=CP-SP=1400-SP=1190
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1190
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Experience &Certified Computer Science/IP instructor

1400*(85/100)=1190
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Tutor

Rs. 1190
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Sp = cp×(100-15)/100 Sp= 1400×85/100= 1190
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Data analyst

Sp = Sp = 1190/-
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Tutor

Rs. 1190.
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CP=Rs 1400 , Loss%=15% By using formula, SP= = Rs = Rs = Rs = Rs 1190 OR (by using unitary method) SP=CP-Loss=Rs (100-15)=Rs 85 When CP is Rs 100 , SP is Rs 85 When CP is Rs 1400 , SP=Rs =Rs 1190
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CP=Rs 1400 , Loss%=15%

By using formula,

SP=[{(100-Loss%)/100}*CP] = Rs[{(100-15)/100}*1400] = Rs [{85/100}*1400] = Rs [85*14] = Rs 1190

OR (by using unitary method)

SP=CP-Loss=Rs (100-15)=Rs 85

When CP is Rs 100 , SP is Rs 85

When CP is Rs 1400 , SP=Rs [(85/100)* 1400]

                                    =Rs 1190

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Technical head and Passionate Teacher

that means selling prise is 85% of cost prise ie SP=(85/100)CP (85/100)1400=1190
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