UrbanPro

Take Class I-V Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

Prove that (sinA-cosA+1)/(sinA+cos-1)=1/(secA-tanA)

Asked by Last Modified  

Follow 13
Answer

Please enter your answer

Personalized CBSE & ICSE Science & Chemistry Coaching.

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved
4 Comments

Tutor

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved
Comments

divide Numerator and Denominator bu Cos A = Tan A - 1 + Sec A / Tan A + 1 - Sec A since (1+ Tan^2 A) = Sec^2 A or 1 = Sec^2 A - Tan^2 A =( Tan A + Sec A - 1) / =( Tan A + Sec A - 1) / = ( Tan A + Sec A - 1) / = ( Tan A + Sec A - 1) / = 1/ {sec A - Tan A}
read more
divide Numerator and Denominator bu Cos A = Tan A - 1 + Sec A / Tan A + 1 - Sec A since (1+ Tan^2 A) = Sec^2 A or 1 = Sec^2 A - Tan^2 A =( Tan A + Sec A - 1) / [Tan A - Sec A+( Sec^2 A - Tan^2 A)] =( Tan A + Sec A - 1) / [(Tan A - Sec A)+( Sec^2 A - Tan^2 A)] = ( Tan A + Sec A - 1) / [- ( Sec A - tan A) + ( Sec^2 A - Tan^2 A)] = ( Tan A + Sec A - 1) / [ ( Sec A - tan A){ Tan A + Sec A - 1] = 1/ {sec A - Tan A} read less
Comments

School Tutor

LS= Sin A - CosA +1 / Sin A + Cos A -1 divide Numerator and Denominator by Cos A = Tan A - 1 + Sec A / Tan A + 1 - Sec A since (1+ Tan^2 A) = Sec^2 A or 1 = Sec^2 A - Tan^2 A =( Tan A + Sec A - 1) / =( Tan A + Sec A - 1) / = ( Tan A + Sec A - 1) / = ( Tan A + Sec A - 1) / = 1/ {sec...
read more
LS= Sin A - CosA +1 / Sin A + Cos A -1 divide Numerator and Denominator by Cos A = Tan A - 1 + Sec A / Tan A + 1 - Sec A since (1+ Tan^2 A) = Sec^2 A or 1 = Sec^2 A - Tan^2 A =( Tan A + Sec A - 1) / [Tan A - Sec A+( Sec^2 A - Tan^2 A)] =( Tan A + Sec A - 1) / [(Tan A - Sec A)+( Sec^2 A - Tan^2 A)] = ( Tan A + Sec A - 1) / [- ( Sec A - tan A) + ( Sec^2 A - Tan^2 A)] = ( Tan A + Sec A - 1) / [ ( Sec A - tan A){ Tan A + Sec A - 1] = 1/ {sec A - Tan A} = RS..proved read less
Comments

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS
Comments

Science loving

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved
Comments

Why we dived thi
Comments

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) 1/(secA-tanA)
Comments

general knowledge,math magician

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved
Comments

SinA-cocA+1/sinA+cosA+1=1/secA+tanA
Comments

View 9 more Answers

Related Questions

what is force?
A force is defined as push or pull exerted on an object.
Ravi Ranjan
What is Verb?
Verb is a word that describes an action, state or occurrence, and forming the main part of the predicate of a sentence, such as walk, talk ,eat, sleep etc.
Hardeep

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

5 Simple Ways To Improve Your Written English
Many people struggle with writing in English and it can seem like a real challenge to improve. Don’t worry, though. Here are some simple steps that you can take to improve your written English and...
I

Iffat A.

1 0
1

How to calculate 1203579 * 9999999 in 2 Sec?
203579 × 9999999 = 1203579-1 | 10000000- 1203579 =120357887964 21 Number in red is 1 less than 1203579. Number in blue is (10000000-1203579). Hence the answer. This method has to be altered...

Reducing Fractions to Lowest Terms
Consider the following two fractions: 1/2 and 2/4 These fractions are equivalent fractions. They both represent the same amount. One half of an orange is equal to two quarters of an orange....
A

Amrtha S.

0 0
0

यण् सन्धि
(क) इ या ई के आगे कोई विजातीय (असमान) स्वर होने पर इ या ई को ‘य्’ हो जाता है। (ख) उ या ऊ के आगे किसी विजातीय(असमान) स्वर के आने पर उ या ऊ को ‘व्’ हो जाता है। (ग) ‘ऋ’...

Maths_Exponents and Power
Exponential Form = 100 = 102, where 2 is the power of 10. Laws of exponents: a-m = 1/ am a m * an = am*n am * an = am*n (am)n = am*n am / bm = (a/b)m a0= 1 (a / b)-m = (b/a)m (-1)odd = -1 (-1)even = 1 ( am / an ) = am-n
A

Amrtha S.

1 0
0

Recommended Articles

An informative subject entirely relies upon the experimented information's and scientific methods, Science is a disciplined way of studying the natural world. Simply you can say, Science is a subject which is completely focused on the facts and evidences concerning the natural and social world. Today, the significance of...

Read full article >

Putting in all your effort yet not scoring well during exams is a common challenge that students face. Students extend their study hours, take guidance from new home tutors yet there is no difference in their performance. Along with students, even some parents become concerned about the deterioration in their child’s performance...

Read full article >

Everyone has this familiar feeling of butterflies fluttering inside stomach whenever there is an exam round the corner. However, managing this jittery sensation and bringing down the anxiety level are what need to be done before an exam. Naturally, how to prepare for exams is the most common issue that daunts a student. Since...

Read full article >

Just because your child has started going to school does not imply you have to appoint a home tutor. Appointment of home tutor or tuition teacher for every child requires the right time and need. It is parents who have to look into the present academic status of their children and take a call, whether to hire a home tutor...

Read full article >

Looking for Class I-V Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class I-V Tuition Classes?

The best tutors for Class I-V Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class I-V Tuition with the Best Tutors

The best Tutors for Class I-V Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more